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| 1. |
If a(-5,7 ) b(-4,-5) c(-1,-6) d(4,5) than find area of ABCD quadrilateral |
| Answer» Given,\xa0vertices of a quadrilateral are\xa0A(-5, 7), B(-4, -5), C(-1, -6) and D(4, 5).Area of quad ABCD = Ar\xa0{tex}\\triangle{/tex}ABD + Ar\xa0{tex}\\triangle{/tex}BCDArea of\xa0{tex}\\triangle{/tex}ABD =\xa0{tex}\\frac{1}{2}{/tex}| (-5)(-5 - 5) + (-4)(5 - 7) + (4)(7 + 5) | = 53 sq unitsArea of\xa0{tex}\\triangle{/tex}\xa0BCD =\xa0{tex}\\frac{1}{2}{/tex}\xa0| (-4)(-6 - 5) + (-1)(5 + 5) + 4(-5 + 6) | = 19 sq unitsTherefore,\xa0Area of quadrilateral\xa0{tex}= 53 + 19 = 72{/tex} sq units. | |