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If a(6 -1) and c(k 8) are three points such that ab=bc find the value of k. |
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Answer» GivenA(6,−1),B(1,3) and C(k,8) Using distance formula AB 2 =BC 2 ⇒(6−1) 2 +(−1−3) 2 =(k−1) 2 +(8−3) 2 ⇒25+16=k 2 +1−2k+25 ⇒k 2 −2k−15=0 ⇒k 2 −5k+3k−15=0 ⇒k(k−5)+3(k−5)=0 ⇒(k−5)(k+3)=0 k−5=0⇒k=5 k+3=0⇒k=−3 GivenA(6,−1),B(1,3) and C(k,8)Using distance formulaAB 2 =BC 2 ⇒(6−1) 2 +(−1−3) 2 =(k−1) 2 +(8−3) 2 ⇒25+16=k 2 +1−2k+25⇒k 2 −2k−15=0⇒k 2 −5k+3k−15=0⇒k(k−5)+3(k−5)=0⇒(k−5)(k+3)=0k−5=0⇒k=5k+3=0⇒k=−3 You haven\'t given b(1,3 ) in your question Wait i am answering Didn\'t understand question |
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