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If a and b are roots of equation x^2+ax-b=0 then find value of a and b

Answer» Let p (x)= x^2 + ax - b =0Now,a+b= - a/1Anda.b=-b/1=~ a = -b / b=~a=-1So...-1 +b = -(-1)b= 1+1=2


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