If A+B=90 and sec A =5/3, then find the value of cosec B

1.	If A+B=90 and sec A =5/3, then find the value of cosec B
Answer» Given A+B=90° i.e,A=90°-Band secA=5/3sec(90°-B) =5/3 (because A=90°-B) CosecB=5/3(because sec(90°-A)=cosecAHence proved A +B=90 A=90-B --------1 SecA = 5/3Sec 90-B =5/3 ( from 1)Cosec B = 5/3 Hence solved Same

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