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If a + b = 90 degree and sec a= 5 / 3 then find the value of cosec b |
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Answer» Sorry sorry i think it is cosec A sec a=5/3a+b =90 so b=90-acosec b =cosec(90-a)=sec a=5/3\xa0 sec a=5/3......h^2=p^2+b^2......5^2=p^2+3^2.....25=p^2+9.......p=4....... cosec=h/p.......so cosec=5/4 How please explain ?? 5/3......... |
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