If A+B=90° and secA=5/3,then find value of CosecB

1.	If A+B=90° and secA=5/3,then find value of CosecB
Answer» A+B=90°secA=5/3We can write A=90°-Bso; secA= 5/3cosec(90-A)=5/3cosec(90-(90-B))=5/3 ( Putting the value of A)cosec(90-90+B)=5/3CosecB=5/3

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