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| 1. |
If a-b, a, a+b are the zeroes of polynomial f(x)=2x^3-6x^2+5x-7,write the value of a |
| Answer» Given polynomial is p(x) =\xa02x3 - 6x2 + 5x - 7Let\xa0{tex}\\alpha{/tex}\xa0= (a - b),\xa0{tex} \\beta{/tex}\xa0= a and\xa0{tex}\\gamma{/tex}\xa0= ( a + b)\xa0Now,\xa0{tex} \\alpha + \\beta + \\gamma{/tex}\xa0=\xa0{tex}-\\frac{(-6)}{2}{/tex}\xa0= 3⇒ ( a - b) + a + (a + b ) = 3⇒ a - b + a + a + b = 3⇒ 3a = 3\xa0⇒ a = 3/3⇒ a = 1So the value of a in given polynomial is 1. | |