If A,B and C are interior angle of triangle than prove that Sin (B+C/2

1.	If A,B and C are interior angle of triangle than prove that Sin (B+C/2) =Cot (A/2)
Answer» A B C are interiors angle then A+B+C= 180PUT the value of B+C in sin( B+C÷ 2)Sin( 180-A/2)=sin(90-A/2)=cos(A/2)Your question is wrong it is not cot it is cos

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