If A,B AND C ARE THE ANGLES OF TRIANGLE SHOW THAT SIN B+C/2=COS A/2

1.	If A,B AND C ARE THE ANGLES OF TRIANGLE SHOW THAT SIN B+C/2=COS A/2
Answer» a+b+c=180°a+b=180°-cOn dividing both sides by 2a+b=90°-c/2Bahut lamba Hai age ka process

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