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If `a , b , c`are consecutive positive integers and `(log(1+a c)=2K ,`then the value of `K`is`logb`(b) `loga`(c) 2(d) 1 |
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Answer» a=m b=m+1 c=m+2 `log(1+ac)=2k` LHS `=log(1+ac)` `=log(1+m(m+2))` `=log(1+m^2+2m)` `=log(m+1)^2` `=2log(m+1)` `=2logb` `2k=2logb` `k=logb`. |
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