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If a, b, c are in AP, and a, x, b and b, y, c are in GP then show that `x^(2), b^(2), y^(2)` are in AP. |
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Answer» `x^(2)=ab, y^(2)=bc and a+c=2b`. `:. x^(2)+y^(2)=(ab+bc)=b(a+c)=2b^(2)`. Hence, `x^(2), b^(2), y^(2)` are in AP. |
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