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| 1. |
If A,B,C are interior angles of a triangle ABC, then show thatsin(B+C/2)=cosA/2 |
| Answer» So easy...we know that A+B+C = 180..Then A= 180-(B+C)...Put this value in place of A...Then u will find...(Sin B+C) = cos {90-(B+C)}By commentary angles property they are equal.. | |