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If `A B C`is an isosceles triangle such that `A B=A C`and `A D`is an altitude from `A`on `B C`. Prove that(i) `/_B=/_C`(ii) `A D`bisects `B C`(iii) `A D`bisects `/_A` |
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Answer» ` In /_ADC and /_ABD` `AB=AC`(given) `/_ADB=/_ADC(each 90^@)` `AD=AD`(common) `/_ADc cong /_ABD(RHS)` `/_B=/_C,BD=CD` `/_BAD=/_CAD`. |
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