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If the altitude from one vertex of a trianglebisects the opposite side, then the triangle is isosceles.GIVEN : A `A B C`such that the altitude `A D`from `A`on the opposite side `B C`bisects `B C`i.e., `B D=D Cdot`TO PROVE : `A B=A C`i.e. the triangle `A B C`is isosceles. |
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Answer» `BO=DC` `In /_ABD and /_ACD` `AD=AD`(common) `/_ADB=/_ADC`(each 90) `BD=CD`(given) `/_ABD cong /_ACD`(SAS) `AB=AC` ABC is isosceles. |
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