1.

Prove that the angle between internal bisector ofone base angle and the external bisector of the other base angle of atriangle is equal to one half of the vertical angle.

Answer» To prove- `/_E=1/2/_A`
By exterior angle theorem
`/_A+/_B=/_ACD`
`1/2/_A+1/2/_B=1/2/_ACD`
`1/2/_A+/_1=/_2`
`/_2=/_1+1/2/_A-(1)`
`In /_BCE`
`/_ECD=/_1+/_E`
`/_2=/_1+/_E-(2)`
From equation 1 and 2
`/_1+/_E=/_1+1/2/_A`
`/_E=1/2/_A`.


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