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Prove that the angle between internal bisector ofone base angle and the external bisector of the other base angle of atriangle is equal to one half of the vertical angle. |
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Answer» To prove- `/_E=1/2/_A` By exterior angle theorem `/_A+/_B=/_ACD` `1/2/_A+1/2/_B=1/2/_ACD` `1/2/_A+/_1=/_2` `/_2=/_1+1/2/_A-(1)` `In /_BCE` `/_ECD=/_1+/_E` `/_2=/_1+/_E-(2)` From equation 1 and 2 `/_1+/_E=/_1+1/2/_A` `/_E=1/2/_A`. |
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