1.

If perpendiculars from any point with an angle onits arms are congruent, prove that it lies on the bisector of that angle.

Answer» To prove-`/_1=/_2`
Proof-`In /_PMB and /_PMB`
PM=PN(given)
BP=BD(common)
`/_PMB=/_PNB(each 90^@)`
`/_PMB cong /_PNB(RHS)`
`/_1=/_2`
BP bisects `/_B`.


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