1.

If `a=(log)_(12)18 , b=(log)_(24)54 ,`then find the value of `a b+5(a-b)dot`

Answer» `a=(log_2 18)/(log_2 12)=(1+2log_2^3)/(2+log_2^3)-(1)`
`b=log_24^54`
`b=(log_2^54)/(log_2^24)=(1+3log_2^3)/(3+log_2^3)-(2)`
From equation 1
`2a+at=1+2t`
`2a-1=(2-a)t`
`t=(2a-1)/(2-a)-(a)`
`3a+bt=1+3t`
`3b-1=t(3-b)`
`t=(3b-1)/(3-b)-(b)`
From a and b
`(2a-1)/(2-a)=(3b-1)/(3-b)`
`6a-2ab-33+b=6b-2-3ab+b`
`6a-2ab+b-6b+3ab-a=3-2`
`ab+5a-5b=1`
`ab+5(a-b)=1`.


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