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If `a=(log)_(12)18 , b=(log)_(24)54 ,`then find the value of `a b+5(a-b)dot` |
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Answer» `a=(log_2 18)/(log_2 12)=(1+2log_2^3)/(2+log_2^3)-(1)` `b=log_24^54` `b=(log_2^54)/(log_2^24)=(1+3log_2^3)/(3+log_2^3)-(2)` From equation 1 `2a+at=1+2t` `2a-1=(2-a)t` `t=(2a-1)/(2-a)-(a)` `3a+bt=1+3t` `3b-1=t(3-b)` `t=(3b-1)/(3-b)-(b)` From a and b `(2a-1)/(2-a)=(3b-1)/(3-b)` `6a-2ab-33+b=6b-2-3ab+b` `6a-2ab+b-6b+3ab-a=3-2` `ab+5a-5b=1` `ab+5(a-b)=1`. |
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