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If a mother is a non tongue roller and Father is a tongue roller, whose father was a non- roller, what is the probability of having a roller daughter?(a) 1/16(b) 1/2(c) 1/4(d) 1/8I have been asked this question in quiz.This intriguing question comes from Numerical Problems topic in section Mendelian Genetics of Cytogenetics

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Right OPTION is (c) 1/4

Best explanation: In this case the FATHER is heterozygous as Rr and mother is homozygous recessive rr. Considering the probability of a GIRL child being ½ we have the probability of a roller as ½. resulted is the product of these TWO PROBABILITIES ½ x ½ = ¼.



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