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If `a ne b ne c`, then solution of equation `|{:(x-a,x-b,x-c),(x-b,x-c,x-a),(x-c, x-a,x-a):}|=0" "is:`A. `x=0`B. `x=a+b+c`C. `x=1/2(a+b+c)(d) x=1/3(a+b+c)`D. `x=1/3(a+b+c)` |
Answer» Correct Answer - D | |