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If a point A (0,2) is equidistant from the point B (3,p) and C (p,5)then find the value of p |
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Answer» AB=ACAB^2=AC^2(0-3)^2+(2-p)^2=(o-p)^2+(2-5)^29+4+p^2-4p=p^2+9-4p=-4p=1 P=1 |
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