If a polynomial x•4-3x•3-6x•2+kx-16 is exactly divisible by x•3-3x+2, find the value of K.

If a polynomial x•4-3x•3-6x•2+kx-16 is exactly divisible by x•

1.	If a polynomial x•4-3x•3-6x•2+kx-16 is exactly divisible by x•3-3x+2, find the value of K.
Answer» Given\xa0p(x) = x4\xa0- 3x3\xa0- 6x2 + kx - 16and g(x) =\xa0x2\xa0- 3x\xa0+ 2On long division of f(x) by g(x) we getNow, remainder = (k - 24)xWhen p(x) is exactly divisible by g(x), then remainder = 0{tex}\\Rightarrow{/tex}\xa0(k - 24)x = 0k - 24 = 0k = 24