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If Aij is the cofactor of the element aij of \(\begin{bmatrix}2 & -3 & 5 \\[0.3em]6 & 0 & 4 \\[0.3em]1 & 5 & -7\end{bmatrix}\) then write the value of (a32 A32). |
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Answer» Theorem: Aij is found by deleting ith rowand jth column, the determinant of left matrix is called cofactor with multiplied by (-1) (i+j). Given: i = 3 and j = 2. A32=(-1)(3+2)(2 × 4-6 × 5) =-1 × (-22) =22 a32=5 a32A32= 5 × 22 =110 |
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