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If alpha and beta are the zeroes of the polynomial 3x2-6x-7x.find alpha2\xa0and beta2

Answer» 3x^2-6x-7x=03x^2-13x=0x(3x-13)=0therfore zeroe are 0 and 13/3alpha^2= o^2=0beta^2=(13/3) = 169/9...........


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