InterviewSolution
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InterviewSolution
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If alpha and beta are the zeros of polynomial ax2+bx+c,then find 1/alpha2+1/beta2 |
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Answer» B^2-2ac÷c^2 1/α²+ 1/β²=α²+β²/(αβ)²α²+β²=(α+β)²-2αβp(x)=ax²+bx+cα+β=-b/aαβ=c/aPutting values we get= (-b/a)² -2*c/a /c²/a²= b²-2ac/c² |
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