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| 1. |
If alpha and bita are zeroes of x*x-6x+k.What is the value of k, if 3alpha-2bita =20? |
| Answer» sum of zeroes=a+b =-b/a=6 a=6-b {given -> 3a-2b=20} 3*(6-b)-2b=20 - - - >18-3b-2b=20 - - - > -5b=2 - - - >b=-2/5 - - - > a=32/5 - - ->product of zeroes =a*b=k {32/5*(-2/5)=k) - - \'>k= - 64/25. | |