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If angle A and angle B are acute angles such that cosA =cosB, show that angle A= angle B. |
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Answer» Hey anshika An In right triangle ABCCosA= AC/AB AND CosB= BC/ABBUT CosA= CosB (given) AC/AB=BC/ABAC=BC THEREFORE Angle A = Angle B ( angle opposite to equal sides are equal Hii Anshika Let us consider two right angle triangles right angled at Q and S respectively.Now,But cos A = cos B\xa0(given)∴ Let In ΔRAS,Using Pythagoras theorem, we haveIn APBQ,Using Pythagoras theorem, we haveSo,\xa0Comparing (i) and (ii), we getSo, by using SSS similar condition∴ |
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