If angle A and B are acute angles such that cosA=cosB,then show that a

1.	If angle A and B are acute angles such that cosA=cosB,then show that angleA =angleB
Answer» Given cos A = cos BHence,\xa0{tex}\\frac{{AC}}{{AB}} = \\frac{{BC}}{{AB}}{/tex}{tex} \\Rightarrow AC = BC{/tex}Since angle opposite to equal sides in a\xa0{tex}\\Delta {/tex}\xa0are equal{tex}\\therefore \\angle B = \\angle A{/tex}Hence proved

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