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if angle of elevation of sun is 60 degree ..find height of tower which casts a shadow of 30 meter

Answer» let AB = tower htAC = shadow = 30 mLC = 60tan c = AB / ACtan\xa060 = AB / 30root 3 = AB / 30AB = tower height = 30 root 3 = 30{tex} \\sqrt{3}{/tex} m


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