If angleA and angle B are acute angle such that cosA=cosB, then show t

1.	If angleA and angle B are acute angle such that cosA=cosB, then show that angleA=angle B.
Answer» Given cos A = cos BHence,\xa0{tex}\\frac{{AC}}{{AB}} = \\frac{{BC}}{{AB}}{/tex}{tex} \\Rightarrow AC = BC{/tex}Since angle opposite to equal sides in a\xa0{tex}\\Delta {/tex}\xa0are equal{tex}\\therefore \\angle B = \\angle A{/tex}Hence proved

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