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if\(\begin{vmatrix}6i&-3i&1\\4&3i&-1\\20&3&i\end{vmatrix}\)= x + iy, then[(6i, 3i, 1) (4, 3i, -1) (20, 3, i)](a) x = 3, y = 1 (b) x = 1, y = 3(c) x = 0, y = 3 (d) x = 0, y = 0 |
Answer» Correct option is (d) x = 0, y = 0 |
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