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if bita and alpa are the zeroes of the quadratic polynomial x²-7x+10

Answer» = x2-5x-2x+10. =x(x-5)-2(x-5) =(x-2) (x-5) =x-2=0=x=2 and x-5 =0=x=5. =a+b= 2+5=7===-(-7/1)==-b/a ==== ab =2*5= 10/1 c/a


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