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If `c |
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Answer» Correct Answer - C the given system is consistent . Therefore `Delta =|{:(1,,1,,-1),(2,,-1,,-c),(-b,,3b,,-c):}|=0` `" or " c+bc -6b +b+ 2c+ 3bc=0` `" or " 3c+4bc-5b=0` `" or " 3c+ 4bc -5b =0` `" or " c=(5b)/(4b+3)` Now `c lt 1` `rArr (5 b)/(4b+3) lt 1 ` `" or " .(5b)/(4b +3) -1 lt 0` `rArr b in (-(3)/(4),3)` |
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