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| 1. |
If cos 47\' = a ; then find the values of sin43\' and tan 43\' in terms of a |
| Answer» sin43=sin(90-47)=cos47=a{tex}\\begin{array}{l}cot43=\\sqrt{1+}\\cos ec^243\\\\=\\sqrt{1+\\frac1{a^2}}=\\frac1a\\sqrt{1+a^2}\\\\\\tan43=\\frac1{cot43}=\\frac a{\\sqrt{1+a2}}\\end{array}{/tex} | |