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If cos `(alpha+beta)=0`, then `sin(alpha-beta)`canbe reduced to : (a) `cosbeta` (b)`cos2beta` ( c) `sinalpha` (d) `sin2alpha` |
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Answer» Given that , `cos(alpha+beta)=0=cos90^(@)` `:. alpha+beta=90^(@)` `:.alpha=90^(@)-beta` `:.sin (alpha-beta)=sin[(90^(@)-beta)]=sin(90^(@)-2beta)=cos2beta` |
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