If cosα/cosβ=m and cosα/sinβ=n, then show that (m²+n²)cos²β=n�

1.	If cosα/cosβ=m and cosα/sinβ=n, then show that (m²+n²)cos²β=n².
Answer» Please let alpha=a bit=b(Cos^2a/cos2b+cos2a/sinb)cos2b=cos2a/sinb(Cos2a sin2b+cosa cosb)cos2b÷÷÷÷÷÷÷÷÷÷÷÷÷÷÷÷÷÷÷÷÷÷÷Cos2bsin2bCos2a(sin2b+cos2b)÷÷÷÷÷Sin2bCos2a. Sin2b+cos2b=1÷÷÷÷÷÷Sin*2b

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