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If cosβ+sinβ=√2 cos β show that cosβ-sin=√2 sinβ

Answer» cosB+sinB=√2cosBsinB=√2cosB-cosBsinB=cosB(√2-1). multiply by (√2+1)sinB×(√2+1)=cosB(√2-1)×(√2+1)√2sinB+sinB=cos(2-1)√2sinB=cosB-sinBHo gya ??


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