If cosec theta +cot theta =p then prove that cos theta =p2 -1/p2+1

1.	If cosec theta +cot theta =p then prove that cos theta =p2 -1/p2+1
Answer» ΞStep 1Ξ Put value of p in RHS i.e. (cotθ+cosecθ)^2-1/(cotθ+cosecθ)^2+1➡➡➡➡➡ΞStep 2Ξ Open whole squares in numerator nd denominator➡➡➡➡➡ΞStep 3Ξ Put {{{cosec^2θ=1+cot^2θ}}}➡you will get this form: (cot^2θ+cotθcosecθ)/(1+cot^2θ+cotθcosecθ)➡➡➡➡➡ΞStep 4Ξ Put cotθ=cosθ/sinθ and cosecθ=1/sinθ➡➡➡➡➡ΞStep 5Ξ Solve and get your LHS.....?

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