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If cot A=15/8 find sinA, cosA, cosecA |
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Answer» cotA=b/pGiven,b/p=15/8By applying Pythagoras theorem we get,P^2+b^2=h^28^2+15^2=h^254+225=h^2h=√64+225therefore,H=17SinA=p/h =8/17CosA=b/h=15/17 and,CosecA=h/b=17/15Hope you will like this answer Given that:- cot A=15/8And we know that:- cot A=b/pSo that, base is 15 & perpendicular is 8 and by the Pythagoras theorem we find 17 as a hypotenuse.Hence,•sin A=p/h=8/17•cos A=b/h=15/17•cosec A=h/p=17/8Hope you understand this very simple way. Cot A=b/pSin A=p/hCosA=b/hCosecA=h/pGiven Cot A=15/8b=15 p=8We find h from Pythagoras theorm h²=b²+p²h=17So,SinA=8/17,Cos=15/17 and Cosec=17/8 |
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