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If cot theta =7/8 then find the value of (1+sin theta)/(1+cos theta)

Answer» Say theta =xCotx=7/8Cosec x=(1+49/64)1\\2/=√113/8{tex}\\frac{1+sinx}{1+cosx}=\\frac{cosecx+1}{cosecx+cotx}{/tex}=(√113/8+1)/(√113/8+7/8)= (√113+8) / (√113+7)\xa0
√113+8/√113+7


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