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if d=HCF (48,72) find the value of d is

Answer» If d is the hcf of 48 and 72 so the value of d will be the hcf of laterfactor of 48 is2,3,4,6,8,12,24 and 48factor of 72 is2,3,4,6,8,9,12,24,36 and 72so the hcf is 24 and d= 24ord = HCF ( 48, 72 )48 = 2 * 2 * 2 * 2 * 372 = 2 * 2 * 2 *3 * 3so HCF = 2 * 2 * 2 * 3➡ 24Answer :- d = HCF ( 48, 72 ) = 24


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