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| 1. |
If d =HCF of 45 and 27 find x and y such that d=27x+45y |
| Answer» 45=27×1+1827=18×1+918=9×2+0HCF=divisor=9d=HCF of 45 and 27d=9d=27-18d=27-(45-27)d=27×2-45d=27x+45yHere,x=2 and y=-1 | |