If d is the HCF of 30,72 find the value of x and y satisfying d=30x+72

1.	If d is the HCF of 30,72 find the value of x and y satisfying d=30x+72y
Answer» But NYRA questn toh aapne galat likha hai Actually woh lcm hoga naa ki hcfAnswer hai x=0,y=5 HCF of 45 and 2745 = (27 x 1) + 1827 = (18 x 1) + 918 = (9 x 2) + 0 Therefore, HCF = 99 = 27 – (18 x 1) = 27 – [45 – (27 x 1)] x 1 [since 18 = 45 – (27 x 1)] = 27 – [45 x 1 – 27 x 1 x 1] = 27 – (45 x 1) + (27 x 1) = 27 + (27 x 1) – (45 x 1) = 27{1 + 1} – (45 x 1) = (27 x 2) – (45 x 1) HCF of 45 and 27 in the form of 27x + 45 is (27 x 2) + (45 x -1).Hence, the values of x and y are 2 and -1.Yeh tha iska ans let me try guys Yahi question maine bhi pucha tha par kisi ne ans nhi diya tha

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