If d is the Hcf of 56 and 72 , find x and y satisfy x and y are not unique . D=56x + 72y

If d is the Hcf of 56 and 72 , find x and y satisfy x and y are not un

1.	If d is the Hcf of 56 and 72 , find x and y satisfy x and y are not unique . D=56x + 72y
Answer» HCF of 56 and 72{tex}\\begin{array}{l}56=8\\times7=2^3\\times7\\\\72=8\\times9=2^3\\times3^2\\\\So\\;HCF(56,72)=2^3=8\\end{array}{/tex}d = 56x + 72y⇒ 8 = 56x + 72yDividing by 8 both sides1= 7x + 9yPut x = 4 and y = –31 = 7 × 4 + 9(–3)= 28 – 271 = 1L.H.S = R.H.S.Put x = –5 and y = 41 = 7(–5) + 9 {tex} \\times {/tex}\xa04= –35 + 361 = 1L.H.S = R.H.S.x = 4, and y = –3x = –5 and y = 4Satisfy the equations\xa0∴ x and y are not unique.