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If ɛ0 and μ0 are the electric permittivity and magnetic permeability of free space respectively, and ɛ and μ are the corresponding quantities in a medium, the index of refraction of the medium in terms of the above parameter is(a) ɛμ/ɛ0μ0(b) (ɛμ/ɛ0μ0)1/2(c) (ɛ0μ0/ɛμ)(d) (ɛ0μ0/ɛμ)1/2 |
Answer» Correct Answer is: (b) (ɛμ/ɛ0μ0)1/2 Velocity of light in vacuum = C = 1/√(μ0ɛ0) Velocity of light in the medium = v = 1/√μɛ. Refractive index = c/v = (μɛ/ɛ0μ0)1/2 |
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