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InterviewSolution
| 1. |
If each edge of a cube is increase by 50%, the percentage in the surface area is |
| Answer» Let the length of each edge of the cube be a cm.After increment, new edge = a + a ×{tex}{50}\\over100{/tex}= a + {tex}{a\\over2}{/tex}={tex}{3a}\\over2{/tex}cmOriginal surface area of the cube = 6a2cm2New surface area of the cube after increment ={tex}6*[{3a\\over2}]^2{/tex}={tex}{27}\\over4{/tex}a2 cm2∴Increase in the surface area of the cube ={tex}{27}\\over2{/tex} a2 – {tex}6{/tex}a2={tex}{15}\\over2{/tex}a2∴Percentage increase in the surface area of the cube ={tex}{{{15}\\over2}a^2\\over6a^2}*100{/tex}={tex}{125}{/tex}∴ There is 125% increase in the surface area of the cube. | |