If edges of cube is increase by 10 percent what percentage LSA is ince

1.	If edges of cube is increase by 10 percent what percentage LSA is incereased.
Answer» Let ‘a’ be the edge of the cube.Surface area of cube = 6a2 sq unitsGiven length of edge is increased by 10%Hence new measure of edge = a + 10% of a = (11a/10)Surface area of cube (after increase) = 6(11a/10)2= (121/100) x 6a2 sq unitsChange in surface area = [(121/100) x 6a2 ] – 6a2 = (21/100) x 6a2% increase = [(21/100) x 6a2] x 100/ [6a2 ]\xa0= 21%

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