1.

If `f:R to R` is defined by `f(x)={{:(,(x-2)/(x^(2)-3x+2),"if "x in R-(1,2)),(,2,"if "x=1),(,1,"if "x=2):}` `"them " lim_(x to 2) (f(x)-f(2))/(x-2)=`

Answer» Correct Answer - B
We have
`f(x)={{:(,(1)/(x-1),"if "x ne 1","2),(,2,"if "x=1),(,1,"if "x=2):}`
`therefore underset(x to 2)lim (f(x)-f(2))/(x-2)`
`underset(x to 2)lim ((1)/(x-1)-1)/(x-2)=underset(x to 2)lim-(x-2)/((x-1)(x-2))=-1`


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