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If `f(x)=|a-1 0a x a-1a x^2a x a|,t h e nf(2x)-f(x)`is divisible by`a`b. `b`c.`c ,d ,e`d. none of theseA. xB. aC. `2a+3x`D. `x^(2)` |
Answer» Correct Answer - A::B::C Applying `R_(3) to R_(3) -xR_(2) " and " R_(2) to R_(2)-xR_(1)` we get `f(x)= |{:(a,,-1,,0),(0,,a+x,,-1),(0,,0,,a+x):}|=a(a+x)^(2)` hence `f(2x)- f(x) =a [(a+2x)^(2) -(a-x)^(2)]` `=a(a+2x-a-x) (a+2x+a+x)` `=ax (2a+3x)` |
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