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If \(f(x) =\begin{cases}\frac{sin\,3x}{sin\,x}, & x \neq 0\\k, & x=0\end{cases}\) is a continuous function, then k =f(x) = {(sin 3x)/(sin x), x ≠ 0, k, x = 0(A) 1(B) 3(C) \(\frac{1}{3}\)(D) 0 |
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Answer» Correct answer is (B) 3 |
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