If f(x) is divided by g(x), it gives quotient as q(x) and remainder as r(x). Then,f(x)=q(x)×g(x)+r(x) where, f(x) is the dividend, q(x) is the quotient, g(x) is the divisor and r(x) is the remainder.(a) True(b) FalseI had been asked this question in my homework.Question is from Division of Polynomial in section Polynomials of Mathematics – Class 10

If f(x) is divided by g(x), it gives quotient as q(x) and remainder as

1.	If f(x) is divided by g(x), it gives quotient as q(x) and remainder as r(x). Then,f(x)=q(x)×g(x)+r(x) where, f(x) is the dividend, q(x) is the quotient, g(x) is the divisor and r(x) is the remainder.(a) True(b) FalseI had been asked this question in my homework.Question is from Division of Polynomial in section Polynomials of Mathematics – Class 10
Answer» RIGHT answer is (a) True To explain I WOULD say: Consider, F(x) is 27x^2-39x, q(x) as 9x+2, g(x) as 3x-5 and remainder is 10. f(x)=q(x)×g(x)+R(x) RHS q(x)×g(x)+r(x)=(9x+2)(3x-5)+10=27x^2-45x+6x-10+10=27x^2-39x, which is equal to LHS. Hence PROVED.

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